如何以编程方式查找两个分支的共同祖先
我正在研究一个项目,其中我的项目集成了git
。为了整合目的,我使用了go-git
库。我的问题是如何以编程方式找到两个分支的共同祖先?我想实现这个功能。看起来像go-git
和其他去库不提供这样的功能。如何以编程方式查找两个分支的共同祖先
回答:
下面是使用go-git
模仿的git merge-base --all
package main import (
"fmt"
"os"
"gopkg.in/src-d/go-git.v4"
. "gopkg.in/src-d/go-git.v4/_examples"
"gopkg.in/src-d/go-git.v4/plumbing"
"gopkg.in/src-d/go-git.v4/plumbing/object"
"gopkg.in/src-d/go-git.v4/plumbing/storer"
)
// store h in set, s, handling nil s if necessary. Return new set.
func store(s map[plumbing.Hash]bool, h plumbing.Hash) map[plumbing.Hash]bool {
if s == nil {
s = make(map[plumbing.Hash]bool)
}
s[h] = true
return s
}
// mergeBase finds best common ancestors between two commits to use in a
// three-way merge. One common ancestor is better than another common ancestor
// if the latter is an ancestor of the former. A common ancestor that does not
// have any better common ancestor is a best common ancestor, i.e. a merge base.
// Note that there can be more than one merge base for a pair of commits.
func mergeBase(s storer.EncodedObjectStorer, a, b plumbing.Hash) ([]plumbing.Hash, error) {
commitA, err := object.GetCommit(s, a)
if err != nil {
return nil, err
}
commitB, err := object.GetCommit(s, b)
if err != nil {
return nil, err
}
// Mapping of direct descendants of each commit we visit
desc := make(map[plumbing.Hash]map[plumbing.Hash]bool)
// Set of commits reachable from a
reachableFromA := make(map[plumbing.Hash]bool)
// Walk commits reachable from A
err = object.NewCommitPreorderIter(commitA, nil, nil).ForEach(func(c *object.Commit) error {
reachableFromA[c.Hash] = true
for _, h := range c.ParentHashes {
desc[h] = store(desc[h], c.Hash)
}
return nil
})
if err != nil {
return nil, err
}
// Set of common commits between a and b
common := make(map[plumbing.Hash]bool)
// Walk commits reachable from B
err = object.NewCommitPreorderIter(commitB, nil, nil).ForEach(func(c *object.Commit) error {
if reachableFromA[c.Hash] {
common[c.Hash] = true
}
for _, h := range c.ParentHashes {
desc[h] = store(desc[h], c.Hash)
}
return nil
})
if err != nil {
return nil, err
}
best := make(map[plumbing.Hash]bool)
// Trim down the set of common commits to only those that are best
for h := range common {
best[h] = true
for child := range desc[h] {
if common[child] {
// there is a descendant to h that is common to both a and b. h is not in best.
delete(best, h)
break
}
}
}
var result []plumbing.Hash
for h := range best {
result = append(result, h)
}
return result, nil
}
// Open an existing repository in a specific folder.
func main() {
CheckArgs("<path> <commitA> <commitB>")
path := os.Args[1]
a := plumbing.NewHash(os.Args[2])
b := plumbing.NewHash(os.Args[3])
r, err := git.PlainOpen(path)
CheckIfError(err)
bases, err := mergeBase(r.Storer, a, b)
CheckIfError(err)
for _, b := range bases {
fmt.Println(b)
}
}
回答:
你可以使用命令的结果:
git merge-base branch1 branch2
以上是 如何以编程方式查找两个分支的共同祖先 的全部内容, 来源链接: utcz.com/qa/261096.html