在选择查询中选择MYSQL

• Z时代
• 2024-01-10
• 分类：问答

您好！我有一个需要输出屏幕数据的查询。
每个屏幕有4个展位可供展示。我需要一个查询有一个结果（因为我只有一个屏幕），并有4个展位（怎么我分配的4个展位）在选择查询中选择MYSQL

这里是我的查询：

$result = DB::select(" 
    SELECT 
     `A`.`scr_name`, 
     `A`.`mission_id`, 
     `B`.`booth_id`, 
     `E`.`name` 
    FROM `tbl_screen` `A` 
    LEFT JOIN 
     `tbl_screen_booths` `B` 
    ON `B`.`screen_id` = `A`.`id` 
    LEFT JOIN 
     `tbl_service_booths` `C` 
    ON `B`.`booth_id` = `C`.`id` 
    LEFT JOIN 
     `tbl_missions_services` `D` 
    ON `C`.`mission_services_id` = `D`.`id` 
    LEFT JOIN 
     `tbl_services` `E` 
    ON `D`.`service_id` = `E`.`id` 
    WHERE `A`.`mission_id` = $mission_id 
    GROUP BY 
     `B`.`booth_id`; 
"); 
return $result; 

我想是这样这样的：

"scr_name": "Test Screen", 
"mission_id": 2, 
"name": "booth1", //index[0] 
"name": "booth2", //index[1] 
"name": "booth3", //index[2] 
"name": "booth4" //index[4] 

我的查询返回的是这样的：

[ 
{ 
"scr_name": "Test Screen", 
"mission_id": 2, 
"booth_id": 7, 
"name": "booth1" 
}, 
{ 
"scr_name": "Test Screen", 
"mission_id": 2, 
"booth_id": 9, 
"name": "booth2" 
}, 
{ 
"scr_name": "Test Screen", 
"mission_id": 2, 
"booth_id": 10, 
"name": "booth3" 
}, 
{ 
"scr_name": "Test Screen", 
"mission_id": 2, 
"booth_id": 11, 
"name": "booth4" 
} 
] 

回答：

$data['scr_name'] = $result[0]->scr_name; 
$data['mission_id'] = $result[0]-> mission_id; 
foreach($result as $index => $item) { 
    $data['name'.($index+1)] => $item->name; 
} 

"scr_name": "Test Screen", 
"mission_id": 2, 
"name1": "booth1", //index[0] 
"name2": "booth2", //index[1] 
"name3": "booth3", //index[2] 
"name4": "booth4" //index[4] 

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