2个数字范围的总和是多少？

  • Z时代
  • 2024-01-10
  • 分类：问答

我想总结两个数字之间的值的范围。我提示用户输入2个号码，如果第一个号码大一些，我想在循环前用第二个号码交换。我怎样才能做到这一点？2个数字范围的总和是多少？

import java.util.Scanner; 
public class Example { 
    public static void main (String []args) { 
     Scanner kb = new Scanner(System.in); 
     int n1 = 0, n2 = 0, count = 0; 
     System.out.print("Enter two limits: "); 
     n1 = kb.nextInt(); 
     n2 = kb.nextInt(); 
     while (n1 <= n2) { 
      count = count + n2; 
      n2--; 
     } 
     System.out.println("The sum from "+ n1 +" to "+ n2 +" is : " + count); 
    } 
}

，我想输出告诉我（如果I型6和10）

the sum from 6 to 10 is 40

，但我的程序输出

the sum from 6 to 5 is 40

我在做什么错？

回答：

您可以使用Math.max(int, int)和Math.min(int, int)（和IntStream，您使用的是Java假设8+）。像，

Scanner kb = new Scanner(System.in); 
System.out.print("Enter two limits: "); 
int n1 = kb.nextInt(); 
int n2 = kb.nextInt(); 
int start = Math.min(n1, n2), stop = Math.max(n1, n2); 
System.out.println("The sum from " + n1 + " to " + n2 + " is : " 
     + IntStream.rangeClosed(start, stop).sum());

如果您不能出于某种原因，还是很方便的小动作使用Math，你可以做一些数学自己的;像

int start = n1; 
if (n2 < n1) { 
    start = n2; 
} 
int stop = n2 + n1 - start;

或

int start = (n1 < n2) ? n1 : n2, stop = n2 + n1 - start;

回答：

Scanner in = new Scanner(System.in); 
int n1; 
int n2; 
int count = 0; 
System.out.print("Enter two limits: "); 
n1 = in.nextInt(); 
n2 = in.nextInt(); 
if (n1 > n2) { 
    n1 += n2; 
    n2 = n1 - n2; 
    n1 -= n2; 
} 
int current = n1; 
while (current <= n2) { 
    count += current; 
    current++; 
} 
System.out.println("The sum from " + n1 + " to " + n2 + " is : " + count);

以上是 2个数字范围的总和是多少？ 的全部内容， 来源链接： utcz.com/qa/258998.html

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