XML：isnil无效元素

  • Z时代
  • 2024-01-10
  • 分类：问答

我有以下XSD片段： <xs:element name="SSN" nillable="true" minOccurs="0"><xs:annotation><xs:documentation>SSN</xs:documentation></xs:annotation><xs:simpleType><xs:restriction base="xs:string"><xs:pattern value="\d{9}"/></xs:restriction></xs:simple类型>XML：isnil无效元素

和相应的XML：

<xsl version="1.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<Provider xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> 
... 
    <Patient> 
    <ProviderPatientNo>00202000</ProviderPatientNo> 
    <LastName>B </LastName> 
    <FirstName>Savannah</FirstName> 
    <SSN>409850124</SSN> 
    <DOB>1998-06-17</DOB> 
    <Gender>1</Gender> 
    <Race>8</Race> 
    <Ethnicity>3</Ethnicity> 
    <PhoneAssessment> 
     <ProviderPhoneAssessmentId>00F62E2A-B726-4573-B459-E216AC78BA06</ProviderPhoneAssessmentId> 
     <CallEndDate>2013-09-16</CallEndDate> 
     <CallEndTime>11:30:00</CallEndTime> 
     <CallDisposition>5</CallDisposition> 
    </PhoneAssessment> 
    </Patient> 
<Patient> 
    <ProviderPatientNo>00202001</ProviderPatientNo> 
    <LastName>C</LastName> 
    <FirstName>Kylie</FirstName> 
    <SSN isnil="true" /> 
    <DOB>2003-06-24</DOB> 
    <Gender>1</Gender> 
    <Race>1</Race> 
    <Ethnicity>2</Ethnicity> 
    <PhoneAssessment> 
     <ProviderPhoneAssessmentId>01089482-E878-4288-B103-A0F28B0A33EC</ProviderPhoneAssessmentId> 
     <CallEndDate>2013-09-25</CallEndDate> 
     <CallEndTime>18:12:00</CallEndTime> 
     <CallDisposition>1</CallDisposition> 
    </PhoneAssessment> 
    </Patient> 
.... 
</xsl>

我试图验证SSN在这个XML。但我收到以下错误：

The 'isnil' attribute is not declared. 
The 'http://www.tn.gov/mental/Schemas/CrisisAssessment:SSN' element is invalid - The value '' is invalid 
according to its datatype 'String' - The Pattern constraint failed.

如何解决此问题？我尝试过各种各样的变化。

我试过XSI更新，但这给了我这个错误，XSI在我的XML文件中指定nowhwere，所以我不认为我可以引用它：

System.Xml.XmlException: 'xsi' is an undeclared namespace. Line 106, position 10. at System.Xml.XmlTextReaderImpl.Throw(Exception e) at System.Xml.XmlTextReaderImpl.Throw(String res, String arg, Int32 lineNo, Int32 linePos) at System.Xml.XmlTextReaderImpl.LookupNamespace(NodeData node) at System.Xml.XmlTextReaderImpl.AttributeNamespaceLookup() at System.Xml.XmlTextReaderImpl.ParseAttributes() at System.Xml.XmlTextReaderImpl.ParseElement() at System.Xml.XmlTextReaderImpl.ParseElementContent() at System.Xml.XmlTextReaderImpl.Read() at System.Xml.Linq.XContainer.ReadContentFrom(XmlReader r) at System.Xml.Linq.XContainer.ReadContentFrom(XmlReader r, LoadOptions o) at System.Xml.Linq.XDocument.Load(XmlReader reader, LoadOptions options) at System.Xml.Linq.XDocument.Load(String uri, LoadOptions options) at System.Xml.Linq.XDocument.Load(String uri) at CMS.UI.WebForms_ManageDataFiles.ValidateXML(String strXMLInstancePath, XElement& xFileDoc) at CMS.UI.WebForms_ManageDataFiles.Master_UploadButton_Click(Object sender, EventArgs e)

布莱恩，我现在想你的XSI代码，但这给了我这个错误：

The 'http://www.tn.gov/mental/Schemas/CrisisAssessment:xsl' element is not declared. 
The attribute 'http://www.w3.org/2001/XMLSchema-instance:isnil' does not match one of the four allowed 
attributes in the 'xsi' namespace.

它给了我同样的错误，当我包括样式表。

回答：

您是否尝试引用xsi？

<SSN xsi:nil="true" />

你也需要有XSI在样式表头

<xsl:stylesheet version="1.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

引用...在你的XML根节点对应的值（从http://www.w3schools.com/schema/schema_schema.asp拍摄）。

<Patients xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

以上是 XML：isnil无效元素 的全部内容， 来源链接： utcz.com/qa/258735.html

回到顶部