如何乘以C++中的4x4浮点矩阵？

• Z时代
• 2024-01-10
• 分类：问答

我有一个简单的结构“mat4”，由float [4] [4]和* =组成，用于乘以4x4矩阵。这需要一个const MAT4 &“RHS”如下：如何乘以C++中的4x4浮点矩阵？

this->m[0][0] = this->m[0][0] * rhs[0][0] + this->m[0][1] * rhs[1][0] + this->m[0][2] * rhs[2][0] + this->m[0][3] * rhs[3][0]; 
this->m[0][1] = this->m[0][0] * rhs[0][1] + this->m[0][1] * rhs[1][1] + this->m[0][2] * rhs[2][1] + this->m[0][3] * rhs[3][1]; 
this->m[0][2] = this->m[0][0] * rhs[0][2] + this->m[0][1] * rhs[1][2] + this->m[0][2] * rhs[2][2] + this->m[0][3] * rhs[3][2]; 
this->m[0][3] = this->m[0][0] * rhs[0][3] + this->m[0][1] * rhs[1][3] + this->m[0][2] * rhs[2][3] + this->m[0][3] * rhs[3][3]; 
this->m[1][0] = this->m[1][0] * rhs[0][0] + this->m[1][1] * rhs[1][0] + this->m[1][2] * rhs[2][0] + this->m[1][3] * rhs[3][0]; 
this->m[1][1] = this->m[1][0] * rhs[0][1] + this->m[1][1] * rhs[1][1] + this->m[1][2] * rhs[2][1] + this->m[1][3] * rhs[3][1]; 
this->m[1][2] = this->m[1][0] * rhs[0][2] + this->m[1][1] * rhs[1][2] + this->m[1][2] * rhs[2][2] + this->m[1][3] * rhs[3][2]; 
this->m[1][3] = this->m[1][0] * rhs[0][3] + this->m[1][1] * rhs[1][3] + this->m[1][2] * rhs[2][3] + this->m[1][3] * rhs[3][3]; 
this->m[2][0] = this->m[2][0] * rhs[0][0] + this->m[2][1] * rhs[1][0] + this->m[2][2] * rhs[2][0] + this->m[2][3] * rhs[3][0]; 
this->m[2][1] = this->m[2][0] * rhs[0][1] + this->m[2][1] * rhs[1][1] + this->m[2][2] * rhs[2][1] + this->m[2][3] * rhs[3][1]; 
this->m[2][2] = this->m[2][0] * rhs[0][2] + this->m[2][1] * rhs[1][2] + this->m[2][2] * rhs[2][2] + this->m[2][3] * rhs[3][2]; 
this->m[2][3] = this->m[2][0] * rhs[0][3] + this->m[2][1] * rhs[1][3] + this->m[2][2] * rhs[2][3] + this->m[2][3] * rhs[3][3]; 
this->m[3][0] = this->m[3][0] * rhs[0][0] + this->m[3][1] * rhs[1][0] + this->m[3][2] * rhs[2][0] + this->m[3][3] * rhs[3][0]; 
this->m[3][1] = this->m[3][0] * rhs[0][1] + this->m[3][1] * rhs[1][1] + this->m[3][2] * rhs[2][1] + this->m[3][3] * rhs[3][1]; 
this->m[3][2] = this->m[3][0] * rhs[0][2] + this->m[3][1] * rhs[1][2] + this->m[3][2] * rhs[2][2] + this->m[3][3] * rhs[3][2]; 
this->m[3][3] = this->m[3][0] * rhs[0][3] + this->m[3][1] * rhs[1][3] + this->m[3][2] * rhs[2][3] + this->m[3][3] * rhs[3][3]; 

我只是想确认是否是正确与否 - 当我将两个矩阵相乘在C++（投影*视图矩阵）和将得到的矩阵交给着色器，屏幕上什么都没有显示出来。

但是，如果我分别给出着色器投影&查看矩阵，并将它们乘以GLSL - 那么它一切正常，结果如预期。

所以矩阵乘法函数一定有问题吗？

回答：

this->m[0][1] = this->m[0][0] * rhs[0][1] + this->m[0][1] * rhs[1][1] + this->m[0][2] * rhs[2][1] + this->m[0][3] * rhs[3][1]; 

以上是 如何乘以C++中的4x4浮点矩阵？ 的全部内容， 来源链接： utcz.com/qa/258696.html