试图从列表打印数量，类型错误：列表索引必须是整数，而不是str的

• Z时代
• 2024-01-10
• 分类：问答

我想读的7试图从列表打印数量，类型错误：列表索引必须是整数，而不是str的

numbers = open('numbers' , 'r') 
nums=[] 
cnt=1 
while cnt<20: 
    nums.append(numbers.readline().rstrip('\n')) 
    cnt += 1 
print nums 
oddNumbers = [] 
multiplesOf7 = [] 
for x in nums: 
    num = int(nums[x]) 
    if num%2 > 0 : 
     oddNumbers.append(num) 
    elif num%7 > 0 : 
     multiplesOf7.append(num) 
print('Odd numbers: ' , oddNumbers) 
print('Multiples of 7: ' , multiplesOf7) 

从文本文件号码（20号）和打印奇数和倍数我越来越

Traceback (most recent call last): ['21', '26', '27', '28', '7', '14', '36', '90', '85', '40', '60', '50', '55', '45', '78', '24', '63', '75', '12'] File "C:/Users/y0us3f/PycharmProjects/Slimanov/oddmultiples.py", line 16, in num = int(nums[x]) TypeError: list indices must be integers, not str

Process finished with exit code 1

回答：

# nums = ['21', '26', '27', '28', '7', '14', '36', '90', '85', '40', '60', '50', '55', '45', '78', '24', '63', '75', '12'] 
for x in nums: 
    # x is '21', '26', etc. 
    num = int(x) 
    ... 

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