的XPath 2个的某些元素

  • Z时代
  • 2024-01-10
  • 分类：问答

我有这样的HTML页面之间选择元素：的XPath 2个的某些元素

<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> 
<tr class="other_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> # Select this 
<tr class="other_label"></tr> # Select this 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> 
<tr class="other_label"></tr>

我要选择带班的TR元素“other_label”这是最后2个TR元素与类“facts_label”之间

我想：

'//tr[@class="other_label" and (preceding-sibling::tr[@class="facts_label"][last()-1]) and (following-sibling::tr[@class="facts_label"][last()])]'

但是，这是我得到

<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> # Got this 
<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> # Got this 
<tr class="other_label"></tr> # Got this 
<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> # Got this 
<tr class="other_label"></tr> # Got this 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> 
<tr class="other_label"></tr>

回答：

的XPath “绝招”：

//tr[ @class='other_label' and count(following-sibling::tr[@class='facts_label'])=1 ]

以上是 的XPath 2个的某些元素 的全部内容， 来源链接： utcz.com/qa/258106.html

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