如果邮件发送成功或错误Codeigniter AJAX如何返回

  • Z时代
  • 2024-01-10
  • 分类：问答

我想要返回一个值从控制器返回到ajax发送电子邮件的时间和地点。以下是一些代码。如果邮件发送成功或错误Codeigniter AJAX如何返回

在下面的代码，我想设置在会话中的闪存数据，并应设置的任一条件，并呼吁它回到了AJAX

控制器

public function send_reply(){ 
     $data = array(
     'from_email' => "[email protected]", 
     'recipient' => $this->input->post('recipient'), 
     'from_name' => "jeeva", 
     'subject' => $this->input->post('subject'), 
     'message' => $this->input->post('message'), 
     ); 
     echo json_encode($data); 
     $this->load->library('email'); 
     $this->email->from($data['from_email'], $data['from_name']); 
     $this->email->to($data['recipient']); 
     $this->email->subject($data['subject']); 
     $this->email->message($data['message']); 
     //Send mail 
     if($this->email->send()) { 
      $this->session->set_flashdata("email_sent","<span> * Email sent successfully. </span> "); 
     //$this->load->view('adminhp'); 
     } else { 
      $this->session->set_flashdata("email_sent","<span> * Error in sending Email.</span> "); 
     // $this->load->view('adminhp'); 
     } 
     }

Ajax代码

// Ajax post for email sending 
$(document).ready( function() { 
$(".mailsub").click(function(event) { 
event.preventDefault(); 
var recipient = jQuery(this).closest('form').find('input.recipient').val(); 
var subject = jQuery(this).closest('form').find('input.subject').val(); 
var message = jQuery(this).closest('form').find('textarea.message').val(); 
jQuery.ajax({ 
type: "POST", 
url: "<?php echo base_url(); ?>" + "index.php/user_authentication/send_reply", 
dataType: 'json', 
data: {recipient: recipient, subject: subject, message:message}, 
success: function(result) { 
if (result) 
{ 
// Show Entered Value 
jQuery("div#result").show(); 
jQuery("div#rslt").html("Sent Successfully"); 
console.log("Success"); 
} 
} 
}); 
}); 
});

我想将它设置为fla在下面的代码SH数据

echo "<br/>"; 
     echo "<div id='result' style='display: none'>"; 
     echo "<div id='rslt' style='display:inline'></div>"; 
     // echo $this->session->flashdata('email_sent'); 
     echo "</div>"; 
     echo "<br/>";

回答：

首先在控制器，你必须呼应消息阿贾克斯

$msg = ''; 
if($this->email->send()) { 
    $msg = 'Email sent successfully'; 
} else { 
    $msg ='Error in sending'; 
    } 
echo $msg;die;

第二只输入反应添加到相应的div：

success: function(result) { 
      if (result) 
      { 
       console.log(result); 
       jQuery("div#result").show(); 
       jQuery("div#rslt").html(result); 
      }

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