找不到ActionMappings或ActionFormBeans集合？

Z时代
2024-01-10
分类：问答

你好家伙的我在新的支柱，而在struss运行的程序，我得到这样的错误....找不到ActionMappings或ActionFormBeans集合？

org.apache.jasper.JasperException: javax.servlet.ServletException: javax.servlet.jsp.JspException: Cannot find ActionMappings or ActionFormBeans collection org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:531) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:439) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:389) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:332) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) root cause javax.servlet.ServletException: javax.servlet.jsp.JspException: Cannot find ActionMappings or ActionFormBeans collection org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:901) org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:830) org.apache.jsp.insert_jsp._jspService(insert_jsp.java:83) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:68) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:416) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:389) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:332) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) root cause javax.servlet.jsp.JspException: Cannot find ActionMappings or ActionFormBeans collection org.apache.struts.taglib.html.FormTag.lookup(FormTag.java:798) org.apache.struts.taglib.html.FormTag.doStartTag(FormTag.java:506) org.apache.jsp.insert_jsp._jspx_meth_html_005fform_005f0(insert_jsp.java:136) org.apache.jsp.insert_jsp._jspx_meth_html_005fhtml_005f0(insert_jsp.java:106) org.apache.jsp.insert_jsp._jspService(insert_jsp.java:73) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:68) javax.servlet.http.HttpServlet.service(HttpServlet.java:722) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:416) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:389) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:332) javax.servlet.http.HttpServlet.service(HttpServlet.java:722)

mycode的都是这样的...... InsertModel.java

package com.cac.struts; 
import java.sql.*; 
public class InsertModel 
{ 
    public boolean insert(String name,String branch,int regd) 
    { 
     boolean b=false; 
     try 
     { 
      Class.forName("sun.jdbc.odbc.JdbcOdbcDriver"); 
      Connection con=DriverManager.getConnection("jdbc:odbc:mohit","system","rock"); 
      PreparedStatement ps=con.prepareStatement("insert into emp values(?,?,?)"); 
      ps.setString(1,name); 
      ps.setString(2,branch); 
      ps.setInt(3,regd); 
      int k=ps.executeUpdate(); 
      if(k>0) 
       b=true; 
     } 
     catch(Exception e) 
     { 
      e.printStackTrace(); 
     } 
     return b; 
    } 
}

InsertForm.java

package com.cac.struts; 
import org.apache.struts.action.ActionForm; 
public class InsertForm extends ActionForm 
{ 
    private int regd; 
    private String name; 
    private String branch; 
    public void setRegd(int r) 
    { 
     regd=r; 
    } 
    public int getRegd() 
    { 
     return regd; 
    } 
    public void setName(String name) 
    { 
     this.name=name; 
    } 
    public String getName() 
    { 
     return name; 
    } 
    public void setBranch(String branch) 
    { 
     this.branch=branch; 
    } 
    public String getBranch() 
    { 
     return branch; 
    } 
}

InsertAction.java

个

package com.cac.struts; 
import org.apache.struts.action.*; 
import javax.servlet.http.*; 
public class InsertAction extends Action 
{ 
    public ActionForward execute(ActionMapping am,ActionForm af,HttpServletRequest hreq,HttpServletResponse hres) throws Exception 
    { 
     String key="failure"; 
     InsertForm iif=(InsertForm)af; 
     int regd=iif.getRegd(); 
     String name=iif.getName(); 
     String branch=iif.getBranch(); 
     InsertModel im=new InsertModel(); 
     boolean b=im.insert(name,branch,regd); 
     if(b) 
     { 
      key="success"; 
     } 
     ActionForward af1=am.findForward(key); 
     return af1; 
    } 
}

的web.xml

<web-app> 
    <servlet> 
     <servlet-name>one</servlet-name> 
     <servlet-class>org.apache.struts.action.ActionServlet</servlet-class> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 
    <servlet-mapping> 
     <servlet-name>one</servlet-name> 
     <url-pattern>*.do</url-pattern> 
    </servlet-mapping> 
</web-app>

支柱-config.html

<struts-config> 
    <form-beans> 
     <form-bean name="insertForm" type="com.cac.struts.InsertForm"> 
    </form-beans> 
    <action-mappings> 
     <action path="/insert" type="com.cac.struts.InsertAction" name="insertForm"> 
      <forward name="success" path="/success.jsp"> 
      <forward name="failure" path="/failure.jsp"> 
     </action> 
    </action-mappings> 
</struts-config>

insert.jsp

<％@标签库URI =“/ WEB-INF /支柱-HTML。 tld“prefix =”html“％>

<html:html> 
    <body bgcolor="yellow"> 
    <center> 
     <h1>Student Application</h1> 
     <html:form action="insert" method="post"> 
      regd<html:text property="regd"/><br><br> 
      name<html:text property="name"/><br><br> 
      branch<html:text property="branch"/><br><br> 
     <html:submit>insert</html:submit> 
     </html:form> 
    </center> 
    </body> 
</html:html>

另外我还使用lib和struts-html.tld中的所有jar文件。请...请帮助我... !!